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Chemistry Question on Balancing a redox reaction

For the redox reaction
MnO4−+C2O42−+H+→Mn2++CO2+H2OMnO_4^-+C_2O^{2-}_4+H^+→Mn^{2+}+CO_2+H_2O
the correct coefficients of the reactants for the balanced equation are

A

MnO4−−16, C2O42−−5, H+−2MnO^-_4-16,\ C_2O^{2-}_4-5,\ H^+-2

B

MnO4−−2, C2O42−−16, H+−5MnO^-_4-2,\ C_2O^{2-}_4-16,\ H^+-5

C

MnO4−−2, C2O42−−5, H+−16MnO^-_4-2,\ C_2O^{2-}_4-5,\ H^+-16

D

MnO4−−5, C2O42−−16, H+−2MnO^-_4-5,\ C_2O^{2-}_4-16,\ H^+-2

Answer

MnO4−−2, C2O42−−5, H+−16MnO^-_4-2,\ C_2O^{2-}_4-5,\ H^+-16

Explanation

Solution

The correct option is (C) :MnO4−−2, C2O42−−5, H+−16MnO^-_4-2,\ C_2O^{2-}_4-5,\ H^+-16.