Question
Question: For the real gases reaction \( 2C{O_{\left( g \right)}} + {O_{2\left( g \right)}} \to 2C{O_{2\left( ...
For the real gases reaction 2CO(g)+O2(g)→2CO2(g) : ΔH=−560 kJ .In 10 litre rigid vessel at 500K .The initial pressure is 70 bar and after the reaction it becomes 40 bar. The change in internal energy is
(A) −557 kJ
(B) −530 kJ
(C) −563 kJ
(D) None of these
Solution
Hint : Internal energy is composed of kinetic energy as well as potential energy of the constituents present in the system. It is represented as (U) .Value of internal energy is either positive or negative depending upon the reaction condition.
Complete Step By Step Answer:
Enthalpy is related to internal energy of the system, pressure of the system and volume of the system. The mathematical expression for such relationship is
H=U+pV
Where H is enthalpy of the system
U Is internal energy of system
p Pressure of system
V Volume of system.
From the given problem we see that reaction is carried out in a vessel of fixed capacity of 10 litre. Hence the reaction proceeds under the isochoric condition.
Therefore, the equation modified and become-
ΔH=ΔU+(p1−p2)V
Where p1 is initial pressure of system as given 70 bar
p2 is final pressure of system as given 40 bar
ΔH=−560 kJ is enthalpy of system
V is volume of system as given 10 litre
Now put all the values in the equation
−560=ΔU+(70−40)10
−560=ΔU+(30)10
On simplifying the equation, we get
−560=ΔU+300
Convert the value of 300 litre-atmosphere into 300kJ by multiplying (0.1)
−560=ΔU+300×0.1
Rearrange the equation in terms of internal energy of system
ΔU=−560+30
ΔU=530 kJ
Hence, the change in internal energy is 530kJ .Therefore, option (2) is the correct option.
Note :
Internal energy is a type of state function which is dependent upon the initial and final states of the chemical reaction.
Reaction process under constant volume condition is known as isochoric process.