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Question

Chemistry Question on Chemical Kinetics

For the reactions,

A

x1−x2{{x}_{1}}-{{x}_{2}}

B

x2−x1{{x}_{2}}-{{x}_{1}}

C

x2+1.5x1{{x}_{2}}+1.5{{x}_{1}}

D

x2−1.5x1{{x}_{2}}-1.5{{x}_{1}}

Answer

x2−1.5x1{{x}_{2}}-1.5{{x}_{1}}

Explanation

Solution

(I) CH4(g)→C(g)+4H(g);C{{H}_{4}}(g)\xrightarrow[{}]{{}}C(g)+4H(g); ΔH=x for four C−H bonds.\Delta H=x\text{ }for\text{ }four\text{ }C-H\text{ }bonds. ∴\therefore BE of (C−H)(C-H) bond =x14=\frac{{{x}_{1}}}{4} (II) C6H6(g)→2C(g)+6H(g){{C}_{6}}{{H}_{6}}(g)\xrightarrow[{}]{{}}2C(g)+6H(g) ΔH=x2=(BE)C−C+6(BE)C−H\Delta H={{x}_{2}}={{(BE)}_{C-C}}+6{{(BE)}_{C-H}} x2=BEC−C+6×x14{{x}_{2}}=B{{E}_{C-C}}+6\times \frac{{{x}_{1}}}{4} (BE)C−C=x2−1.5x1{{(BE)}_{C-C}}={{x}_{2}}-1.5{{x}_{1}}