Question

For the reaction,

$(x + y)kJmol^{- 1}$

at constant temperature, $(x - y)kJmol^{- 1}$ is.

• A. – RT
• B.
  • RT
• C. – 3RT
• D.
  • 3RT

Answer 1

Answer: (C)

– 3RT

Answer 2

$6kJmol^{- 1}$ ; $16Jmol^{- 1}K^{- 1}$

so, $375^{o}C$.