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Question: For the reaction \(P C l _ { 5 } ( g )\) ⇌ <img src="https://cdn.pureessence.tech/canvas_491.png?to...

For the reaction PCl5(g)P C l _ { 5 } ( g ) ⇌ .

A

Kp=KcK _ { p } = K _ { c }

B

Kp=Kc(RT)−1K _ { p } = K _ { c } ( R T ) ^ { - 1 }

C

Kp=Kc(RT)K _ { p } = K _ { c } ( R T )

D

Kp=Kc(RT)2K _ { p } = K _ { c } ( R T ) ^ { 2 }

Answer

Kp=Kc(RT)K _ { p } = K _ { c } ( R T )

Explanation

Solution

Δn\Delta n =2-1=1

Kp=Kc(RT)K _ { p } = K _ { c } ( R T )