Question
Question: For the reaction, N<sub>2</sub>O<sub>5</sub>¾® 2NO<sub>2</sub> + \(\frac{1}{2}\)O<sub>2</sub> Given...
For the reaction, N2O5¾® 2NO2 + 21O2
Given ,−dtd[N2O5] = K1[N2O5]
dtd[NO2]= K2[N2O5] and dtd[O2] = K3[N2O5]
The relation in between K1, K2 and K3 is -
A
2K1 = K2 = 4K3
B
K1 = K2 = K3
C
2K1 = 4K2 = K3
D
None of these
Answer
2K1 = K2 = 4K3
Explanation
Solution
−dtd[N2O5]= 21 dtd[NO2] = 2dtd[O2]