Solveeit Logo

Question

Question: For the reaction, N<sub>2</sub>O<sub>5</sub>¾® 2NO<sub>2</sub> + \(\frac{1}{2}\)O<sub>2</sub> Given...

For the reaction, N2O5¾® 2NO2 + 12\frac{1}{2}O2

Given ,d[N2O5]dt- \frac{d\lbrack N_{2}O_{5}\rbrack}{dt} = K1[N2O5]

d[NO2]dt\frac{d\lbrack NO_{2}\rbrack}{dt}= K2[N2O5] and d[O2]dt\frac{d\lbrack O_{2}\rbrack}{dt} = K3[N2O5]

The relation in between K1, K2 and K3 is -

A

2K1 = K2 = 4K3

B

K1 = K2 = K3

C

2K1 = 4K2 = K3

D

None of these

Answer

2K1 = K2 = 4K3

Explanation

Solution

d[N2O5]dt- \frac{d\lbrack N_{2}O_{5}\rbrack}{dt}= 12\frac { 1 } { 2 } d[NO2]dt\frac{d\lbrack NO_{2}\rbrack}{dt} = 2d[O2]dt\frac{d\lbrack O_{2}\rbrack}{dt}