Question

For the reaction, N₂ (g) + 3H₂ (g) 2NH₃ (g) DH = –93.6 kJ/mol

For reaction, $\frac { 1 } { 2 }$N₂ (g) + $\frac { 3 } { 2 }$H₂ (g)NH₃ (g) DH¢

Which of the following is/are correct?

• A. At any given temperature K_eq
• B. On increasing temperature K_eq increases at a greater proportion than...
• C. Both (1)&(2) are correct
• D. Neither (1) nor (2) is correct

Answer 1

Answer: (A)

At any given temperature K_eq

Answer 2

DH ^¢ = $\frac { - 93.6 } { 2 }$kJ/mol

\ ln=×$\frac { \Delta \mathrm { T } } { \mathrm { T } _ { 1 } \mathrm {~T} _ { 2 } }$ and ln$\frac { \left( \mathrm { K } _ { \mathrm { eq } } ^ { \prime } \right) _ { \mathrm { T } _ { 2 } } } { \left( \mathrm {~K} _ { \mathrm { eq } } ^ { \prime } \right) _ { \mathrm { T } _ { 1 } } }$=$\frac { \Delta \mathrm { H } ^ { \prime } } { \mathrm { R } }$×$\frac { \Delta \mathrm { T } } { \mathrm { T } _ { 1 } \mathrm {~T} _ { 2 } }$

On increasing temperature K_eq & both decreases.