Question

For the reaction $N_{2} + 3H_{2} \rightarrow 2NH_{3}$ how are the rate of reaction expression inter related $\frac{d\lbrack H_{2}\rbrack}{dt}$ and $\frac{d\lbrack NH_{3}\rbrack}{dt}?$

• A. $- \frac{1}{3}\frac{d\lbrack H_{2}\rbrack}{dt} = + \frac{1}{2}\frac{d\lbrack NH_{3}\rbrack}{dt}$
• B. $- \frac{1}{2}\frac{d\lbrack H_{2}\rbrack}{dt} = + \frac{1}{3}\frac{d\lbrack NH_{3}\rbrack}{dt}$
• C. $+ \frac{1}{2}\frac{d\lbrack H_{2}\rbrack}{dt} = - \frac{1}{3}\frac{d\lbrack NH_{3}\rbrack}{dt}$
• D. $+ \frac{1}{3}\frac{d\lbrack H_{2}\rbrack}{dt} = - \frac{1}{2}\frac{d\lbrack NH_{3}\rbrack}{dt}$

Answer 1

Answer: (A)

$- \frac{1}{3}\frac{d\lbrack H_{2}\rbrack}{dt} = + \frac{1}{2}\frac{d\lbrack NH_{3}\rbrack}{dt}$

Answer 2

For the reaction $N_{2} + 3H_{2} \rightarrow 2NH_{3}$

$- \frac{1}{3}\frac{d\lbrack H_{2}\rbrack}{dt} = + \frac{1}{2}\frac{d\lbrack NH_{3}\rbrack}{dt}$