For the reaction, (N\_{2}+3 H\_{2} 2 N H ; \Delta H=) ? | Chemistry | SolveeIt

For the reaction, $N_{2}+3 H_{2} 2 N H ; \Delta H=$ ?

$\Delta E=+\,2RT$

$\Delta E-\,2RT$

$\Delta E+\,RT$

$\Delta E-\,RT$

Answer

$\Delta E-\,2RT$

Explanation

$N_{2}+3 H_{2} 2 N H_{3}\Delta H=\Delta E+\Delta n R T$
$\Delta n=2-4=-2$
$\therefore \Delta H=\Delta E+(-2) R T$
$\Delta H=\Delta E-2 R T$

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