Solveeit Logo

Question

Question: For the reaction <img src="https://cdn.pureessence.tech/canvas_487.png?top_left_x=1704&top_left_y=0&...

For the reaction 2CO(g)2 \mathrm { CO } ( \mathrm { g } ) , the partial pressure of CO2\mathrm { CO } _ { 2 } and CO are 2.0 and 4.0 atm respectively at equilibrium. The KpK _ { p } for the reaction is.

A

0.5

B

4.0

C

8.0

D

32.0

Answer

8.0

Explanation

Solution

Kp=[Pco]2[PCO2]=4×42=8\mathrm { K } _ { \mathrm { p } } = \frac { \left[ \mathrm { P } _ { \mathrm { co } } \right] ^ { 2 } } { \left[ \mathrm { P } _ { \mathrm { CO } _ { 2 } } \right] } = \frac { 4 \times 4 } { 2 } = 8 .