Question

For the reaction:
${I^ - } + ClO_3^ - + {H_2}S{O_4} \to C{l^ - } + HSO_4^ - + {I_2}$
The correct statement(s) in the balanced equation is/are:
(This question has multiple correct options)
A. Stoichiometric coefficient $HSO_4^ -$ of is 6
B. Iodide is oxidized
C. Sulphur is reduced
D. ${H_2}O$ is one of the products

Answer 1

Hint- In order to deal with this question we will use the concept of stoichiometry first we will balance the given reaction by following some steps which are mentioned in the solution further according to this balance reaction we will find the required answer.

Complete step-by-step answer:
Given reaction:
${I^ - } + ClO_3^ - + {H_2}S{O_4} \to C{l^ - } + HSO_4^ - + {I_2}$
In order to balance the above reaction we have to follow below steps:
Step 1: Write the two half reactions
Reduction half reaction:
$ClO_3^ - \to C{l^ - }$
Oxidation half reaction:
${I^ - } \to {I_2}$
Step 2: Balance the atoms other than O and H

$$\Rightarrow ClO_3^ - \to C{l^ - } \\\ \Rightarrow 2{I^ - } \to {I_2} \\\$$

Step 3: Balance the O and H atoms using ${H_2}O$ and ${H^ + }$

$$\Rightarrow ClO_3^ - + 6{H^ + } \to C{l^ - } + 3{H_2}O \\\ \Rightarrow 2{I^ - } \to {I_2} \\\$$

Step4: Balance the charges using electrons

$$\Rightarrow ClO_3^ - + 6{H^ + } + 6{e^ - } \to C{l^ - } + 3{H_2}O \\\ \Rightarrow 2{I^ - } \to {I_2} + 2{e^ - } \\\$$

Step5: Multiply the oxidation half reaction with 3 and add to the reduction half reaction to get the net reaction after cancelling the electrons.

$$\Rightarrow ClO_3^ - + 6{H^ + } + 6{e^ - } \to C{l^ - } + 3{H_2}O \\\ \Rightarrow 6{I^ - } \to 3{I_2} + 6{e^ - } \\\$$

Net balance reaction:
$\Rightarrow 6{I^ - } + ClO_3^ - + 6{H_2}S{O_4} \to C{l^ - } + 6HSO_4^ - + 3{I_2} + 3{H_2}O$
Here ${H^ + }$ is coming from ${H_2}S{O_4}$ so we can write the ${H_2}S{O_4}$ in place of ${H^ + }$ . The 12 $H$ from LHS is balanced by $6HSO_4^ - \& 3{H_2}O$.
Hence stoichiometric coefficient of $HSO_4^ -$ is 6, iodide is oxidised from ${I^ - } \to {I_2}$ and ${H_2}O$ is one of the products.
So, options A, B and D are correct.

Note- Stoichiometry is a segment of chemistry that involves using the relationships in a chemical reaction between reactants and/or products to decide desired quantitative results. So the simply translated stoichiometry means the calculation of components.
Stoichiometry is essentially the quantitative relationship between the number of moles (and thus the mass) in a chemical reaction between specific compounds and reactants. Chemical reactions must be regulated, or in other words , the number of different atoms in the compounds must be the same as in the reactants. The stoichiometry is used to calculate the quantity of products and reactants produced or needed in a given reaction.