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Question: For the reaction: \(H_{2(g)} + Cl_{2(g)} \rightarrow 2HCl;\Delta H = - 44kcal\) what is the enthalpy...

For the reaction: H2(g)+Cl2(g)→2HCl;ΔH=−44kcalH_{2(g)} + Cl_{2(g)} \rightarrow 2HCl;\Delta H = - 44kcal what is the enthalpy of decomposition of HCl?

A

+44 kcal/mol

B

-44 kcal/mol

C

– 22 kcal/mol

D
  • 22 kcal /mol
Answer
  • 22 kcal /mol
Explanation

Solution

: Enthalpy of decomposition of HCl will be 442=22kcal/mol\frac{44}{2} = 22kcal/mol