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Chemistry Question on Rate of a Chemical Reaction

For the reaction H2(g)+I2(g)<=>2HI(g) {H2_{(g)} + I2_{(g)} <=> 2HI_{(g)} }, the rate of reaction is expressed as

A

Δ[H2]Δ t=12Δ[I2]Δ t=−Δ[HI]Δ t\frac{\Delta\left[H_{2}\right]}{\Delta \,t}=\frac{1}{2} \frac{\Delta\left[I_{2}\right]}{\Delta\,t}=-\frac{\Delta\left[HI\right]}{\Delta\,t}

B

−Δ[I2]Δt=−Δ[H2]Δt=12Δ[HI]Δt-\frac{\Delta\left[I_{2}\right]}{\Delta t}=-\frac{\Delta\left[H_{2}\right]}{\Delta t}=\frac{1}{2} \frac{\Delta\left[HI\right]}{\Delta t}

C

−Δ[I2]Δt=−Δ[H2]Δt=Δ[HI]2Δt-\frac{\Delta\left[I_{2}\right]}{\Delta t}=-\frac{\Delta\left[H_{2}\right]}{\Delta t}= \frac{\Delta\left[HI\right]}{2\Delta t}

D

none of these

Answer

−Δ[I2]Δt=−Δ[H2]Δt=12Δ[HI]Δt-\frac{\Delta\left[I_{2}\right]}{\Delta t}=-\frac{\Delta\left[H_{2}\right]}{\Delta t}=\frac{1}{2} \frac{\Delta\left[HI\right]}{\Delta t}

Explanation

Solution

Answer (b) −Δ[I2]Δt=−Δ[H2]Δt=12Δ[HI]Δt-\frac{\Delta\left[I_{2}\right]}{\Delta t}=-\frac{\Delta\left[H_{2}\right]}{\Delta t}=\frac{1}{2} \frac{\Delta\left[HI\right]}{\Delta t}