Question

For the reaction $H _{2}( g )+ Br _{2}( g ) \rightarrow 2 HBr ( g )$, the experiment data suggested that $r = k \left[ H _{2}\right]\left[ Br _{2}\right]^{1 / 2} .$ The molecularity and order of the reaction are respectively:

• A. $2, \frac{3}{2}$
• B. $\frac{3}{2}, \frac{3}{2}$
• C. 1,1
• D. $1, \frac{1}{2}$

Answer 1

Answer: (A)

$2, \frac{3}{2}$

Answer 2

$H _{2}( g )+ Br _{2}( g ) \rightarrow 2 HBr ( g )$
$r = k \left[ H _{2}\right]\left[ Br _{2}\right]^{1 / 2}$
Molecularity $=2$
Order $=1+0.5=1.5=3 / 2$