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Question: For the reaction equilibrium <img src="https://cdn.pureessence.tech/canvas_222.png?top_left_x=1441&t...

For the reaction equilibrium ⇌, the concentrations of and NO2\mathrm { NO } _ { 2 } at equilibrium are 4.8×10−24.8 \times 10 ^ { - 2 }and respectively. The value of KcK _ { c } for the reaction is.

A

3.3×1023.3 \times 10 ^ { 2 }

B

3×10−13 \times 10 ^ { - 1 }

C

3×10−33 \times 10 ^ { - 3 }

D

3×1033 \times 10 ^ { 3 }

Answer

3×10−33 \times 10 ^ { - 3 }

Explanation

Solution

=[1.2×10−2]2[4.8×10−2]= \frac { \left[ 1.2 \times 10 ^ { - 2 } \right] ^ { 2 } } { \left[ 4.8 \times 10 ^ { - 2 } \right] } =0.3×10−2= 0.3 \times 10 ^ { - 2 } =3×10−3= 3 \times 10 ^ { - 3 }