Question

For the reaction, $C(s)+CO_{2}(g)2CO(g)$ the partial pressure of $CO_{2}$ and $CO$ are $2.0$ and $4.0$ arm respectively then equilibrium $K_{p}$ for the reaction will be

• A. $0.5$
• B. $8.0$
• C. $4.0$
• D. $32$

Answer 1

Answer: (B)

$8.0$

Answer 2

For the reaction, $C(s)+ CO _{2}(g) 2 CO (g)$ $K_{p}=\frac{\text { partial pressure of gasseous products }}{\text { partial pressure of gasseous reactans }}$ $=\frac{P_{C O}^{2}}{P_{C O_{2}}}=\frac{4 \times 4}{2}=8$