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Chemistry Question on Thermodynamics

For the reaction C2H5OH(l)+3O2(g)→2CO2(g)+3H2O(l)C_2H_5OH(l)+3O_2(g)→ 2CO_2(g)+3H_2O(l) which one is true:

A

∆H=∆E–RT∆H=∆E–RT

B

∆H=∆E+RT∆H=∆E+RT

C

∆H=∆E+2RT∆H=∆E+2RT

D

∆H=∆E+2RT∆H=∆E+2RT

Answer

∆H=∆E–RT∆H=∆E–RT

Explanation

Solution

C2H5OH(l)+3O2(g)→2CO2(g)+3H2O(l)C_2H_5OH(l)+3O_2(g)→ 2CO_2(g)+3H_2O(l)

We know that

△H=△E+P△V△H=△E+P△V

From the ideal gas equation PV=nRTPV = nRT

△H=△E+△ng​RT△H=△E+△n_g​RT

△ng△n_g​= No. of gaseous moles of product − No. of gaseous moles of reactant

△ng△n_g​=2−3=−1= 2-3 = -1

Then, △H=△E−RT△H=△E−RT

So, the correct option is (A): △H=△E−RT△H=△E−RT