Question

For the reaction A2(g) + 2B2 $\rightleftharpoons$ 2C2(g)

the partial pressure of A2, B2 at equilibrium are 0.80 atm and 0.40 atm respectively. The pressure of the system is 2.80 atm. The equilibrium constant Kp will be

• A. 20
• B. 5.0
• C. 0.02
• D. 0.2

Answer 1

Answer: (A)

20

Answer 2

A2(g) + 2B2(g) $\rightleftharpoons$ 2C2(g)

PA2 = 0.80 atm., PB 2 = 0.4 atm.

Total pressure of the system = 2.8 atm.

\PC 2 = 2.8 – 0.8 – 0.4 = 1.6

$K_{p} = \frac{P_{C_{2}}^{2}}{P_{A_{2}} \times P_{B_{2}}^{3}} = \frac{(1.6)^{2}}{0.8 \times (0.4)^{2}} = 20$