Question

For the reaction $A$ ⇌ $B$ at $N_{2} + 3H_{2}$ the value of equilibrium constant$2NH_{3}$ is 50. When the equilibrium concentration of both is$N_{2}$, the value of $H_{2}$ under the same conditions will be.

• A. 0.002
• B. 0.2
• C. 50.0
• D. $Cl_{2}$

Answer 1

Answer: (C)

50.0

Answer 2

For the reaction $H_{2}S$ ⇌ 2HI

$H_{2}$

So $S_{2}$ ∴50.0