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Question: For the reaction \(373K\)⇌\(111.9Jmol^{- 1}K^{- 1}\)...

For the reaction 373K373K⇌111.9Jmol−1K−1111.9Jmol^{- 1}K^{- 1}

A

37.3Jmol−1K−137.3Jmol^{- 1}K^{- 1}

B

100Jmol−1K−1100Jmol^{- 1}K^{- 1}

C

74.6Jmol−1K−174.6Jmol^{- 1}K^{- 1}

D

ΔS\Delta S

Answer

100Jmol−1K−1100Jmol^{- 1}K^{- 1}

Explanation

Solution

3kJ3kJ

Since (CV=20J/K)(C_{V} = 20J/K)

Than H2(g)+Cl2(g)→2HCl(g)H_{2(g)} + Cl_{2(g)} \rightarrow 2HCl_{(g)}.