Question

For the reaction,

2NO(g) + 2H₂(g) ¾® N₂(g) + 2H₂O(g)

The rate expression can be written in the following ways :

$\frac{d\lbrack N_{2}\rbrack}{dt}$= k₁[NO] [H₂] ; $\frac{d\lbrack H_{2}O\rbrack}{dt}$= k₂[NO] [H₂]

–$\frac{d\lbrack NO\rbrack}{dt}$= k₃[NO] [H₂] ; – $\frac{d\lbrack H_{2}\rbrack}{dt}$= k₄[NO] [H₂]

The relationship between k₁, k₂, k₃, k₄ is -

• A. k₂ = k₁ = k₃ = k₄
• B. k₂ = 2k₁ = k₃ = k₄
• C. k₂ = 2k₃ = k₁ = k₄
• D. k₂ = k₁ = k₃ = 2k₄

Answer 1

Answer: (B)

k₂ = 2k₁ = k₃ = k₄

Answer 2

2NO + 2H₂ ¾® N₂ + 2H₂O

$\frac{r_{NO}}{2}$=$\frac{r_{H_{2}}}{2}$= $\frac{r_{N_{2}}}{1}$= $\frac{r_{H_{2}O}}{2}$

$\frac{K_{3} \times \lbrack NO\rbrack \times \lbrack H_{2}\rbrack}{2}$=$\frac{K_{4} \times \lbrack NO\rbrack \times \lbrack H_{2}\rbrack}{2}$

= $\frac{K_{1} \times \lbrack NO\rbrack \times \lbrack H_{2}\rbrack}{1}$=$\frac{K_{2} \times \lbrack NO\rbrack \times \lbrack H_{2}\rbrack}{2}$

\ K₃ = K₄ = 2K₁ = K₂