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Question: For the reaction \(2NO_{2(g)}\)⇌ ![](https://cdn.pureessence.tech/canvas_427.png?top_left_x=1200&top...

For the reaction 2NO2(g)2NO_{2(g)}⇌ Kc=1.8×10−6K_{c} = 1.8 \times 10^{- 6}at 185oC185^{o}C. At 185oC185^{o}C, the value of Kc′K_{c}^{'} for the reaction NO(g)+12O2(g)NO_{(g)} + \frac{1}{2}O_{2(g)}⇌NO2(g)NO_{2(g)} is

A

0.9×1060.9 \times 10^{6}

B

7.5×1027.5 \times 10^{2}

C

1.95×10−31.95 \times 10^{- 3}

D

1.95×1031.95 \times 10^{3}

Answer

7.5×1027.5 \times 10^{2}

Explanation

Solution

Reaction is reversed and halved.

∴Kc′=1Kc\therefore K_{c}^{'} = \frac{1}{\sqrt{K_{c}}}; Kc′=11.8×10−6K_{c}^{'} = \frac{1}{\sqrt{1.8 \times 10^{- 6}}} =7.5×1027.5 \times 10^{2}