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Question

Chemistry Question on Equilibrium

For the reaction 2NO2(g)<=>N2O4(g),Kp/Kc {2NO_{2(g)} <=> N2O_{4(g)}, K_{p}/K_{c}} is equal to

A

1RT\frac{1}{RT}

B

RT\sqrt{RT}

C

RTRT

D

(RT)2\left(RT\right)^{2}

Answer

1RT\frac{1}{RT}

Explanation

Solution

2NO2(g)<=>N2O4(g) {2NO_{2(g)} <=> N2O_{4(g)}} Δn=1−2=−1\Delta n=1-2=-1 Kp=Kc(RT)ΔnK_{p}=K_{c}\left(RT\right)^{\Delta n} KpKc=(RT)−1\frac{K_{p}}{K_{c}}=\left(RT\right)^{-1}