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Question

Chemistry Question on Equilibrium

For the reaction
2N2O5→4NO2+02
Rate of the reaction is:

A

Δ[N2O5]Δt=12Δ[NO2]Δt\frac{Δ[N_2O_5]}{Δ t}=\frac{1}{2} \frac{Δ[ΝΟ_2]}{Δt}

B

−Δ[N2O5]Δt=12Δ[NO2]Δt-\frac{Δ[N_2O_5]}{Δ t}=\frac{1}{2} \frac{Δ[ΝΟ_2]}{Δt}

C

Δ[O2]Δt=Δ[NO2]Δt\frac{Δ[O_2]}{Δ t}= \frac{Δ[ΝΟ_2]}{Δt}

D

−Δ[O2]Δt=Δ[NO2]Δt-\frac{Δ[O_2]}{Δ t}= \frac{Δ[ΝΟ_2]}{Δt}

Answer

−Δ[N2O5]Δt=12Δ[NO2]Δt-\frac{Δ[N_2O_5]}{Δ t}=\frac{1}{2} \frac{Δ[ΝΟ_2]}{Δt}

Explanation

Solution

The correct option is(B):−Δ[N2O5]Δt=12Δ[NO2]Δt-\frac{Δ[N_2O_5]}{Δ t}=\frac{1}{2} \frac{Δ[ΝΟ_2]}{Δt}