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Question: For the reaction 2A + 3B ® 4C the rate of reaction may be represented as...

For the reaction 2A + 3B ® 4C the rate of reaction may be represented as

A

r = – 2 d[A]dt\frac{d\lbrack A\rbrack}{dt} = – 3 d[B]dt\frac{d\lbrack B\rbrack}{dt}= 4 d[C]dt\frac{d\lbrack C\rbrack}{dt}

B

r = – 6d[A]dt\frac{d\lbrack A\rbrack}{dt} = – 4 d[B]dt\frac{d\lbrack B\rbrack}{dt} = 3 d[C]dt\frac{d\lbrack C\rbrack}{dt}

C

r = –14\frac { 1 } { 4 } d[C]dt\frac{d\lbrack C\rbrack}{dt}

D

r = –14\frac { 1 } { 4 } d[C]dt\frac{d\lbrack C\rbrack}{dt}

Answer

r = –\frac { 1 } { 4 }$$\frac{d\lbrack C\rbrack}{dt}

Explanation

Solution

For the reaction 2A + 3B ® 4C, the rate of reaction is represented as

–12\frac{1}{2} d[A]dt\frac{d\lbrack A\rbrack}{dt} = –13\frac{1}{3} d[B]dt\frac{d\lbrack B\rbrack}{dt}=14\frac { 1 } { 4 } d[C]dt\frac{d\lbrack C\rbrack}{dt}