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Question: For the reaction \(- 286kJ/mole\) ⇌ \(2H_{2}O_{2}(l) \rightarrow 2H_{2}O(l) + O_{2}(g)\) at \(- 196...

For the reaction

−286kJ/mole- 286kJ/mole ⇌ 2H2O2(l)→2H2O(l)+O2(g)2H_{2}O_{2}(l) \rightarrow 2H_{2}O(l) + O_{2}(g) at −196kJ/mole- 196kJ/mole and 1 atm. pressure, 146kJ/mole146kJ/mole Then the change in internal energy −494kJ/mole- 494kJ/mole is.

A

– 874 kJ

B

– 871.53 kJ

C

– 876.47 kJ

D
  • 874 kJ
Answer

– 874 kJ

Explanation

Solution

For this reaction C(ghjk)→C(xzsQkbV)C_{(ghjk)} \rightarrow C_{(xzsQkbV)}than 0oC0^{o}C