Solveeit Logo

Question

Chemistry Question on Structure of atom

For the Paschen series the values of n1n_{1} and n2n_{2} in the expression ΔE=Rhc(1n121n22)\Delta E=Rhc\left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right) are

A

n1=1,n2=2,3,4........n_{1}=1, n_{2}=2,3,4 ........

B

n1=2,n2=3,4,5........n_{1}=2, n_{2}=3,4,5 ........

C

n1=3,n2=4,5,6........n_{1}=3, n_{2}=4,5,6 ........

D

n1=4,n2=5,6,7........n_{1}=4, n_{2}=5,6,7 ........

Answer

n1=3,n2=4,5,6........n_{1}=3, n_{2}=4,5,6 ........

Explanation

Solution

Paschen series is the third series of hydrogen spectrum and lies in the infrared region, therefore for this series, n1=3n_{1}=3 and n2>n1n_{2}>n_{1}, ie, 4,5,6,4,5,6, \ldots