Question

For the particle executing SHM the displacement x is given by x = A cosωt. Identify which represents variation of potential energy as a function of time t and displacement x

• A. I, III
• B. II,IV
• C. II, III
• D. I,IV

Answer 1

Answer: (A)

I, III

Answer 2

x = A cos ωt

PE = $\frac { 1 } { 2 } m \omega ^ { 2 } x ^ { 2 } = \frac { 1 } { 2 } m \omega ^ { 2 } A ^ { 2 } \cos ^ { 2 } \omega t$

That is, at t = 0 potential energy is maximum and potential energy αx² So choice is I and III.