Question

For the oxidation of glucose, D_rHŗ = – 2808 kJ/mol and D_rGŗ = – 3000 kJ/mol

25% of energy of the isoxidised for muscle work. Therefore, in order to climb a hill of height 500 metres, how many gm of glucose is required for a man of mass 100 kg ? g = 10 m/s².

• A. 100 gm
• B. 180 gm
• C. 200 gm
• D. 120 gm

Answer 1

Answer: (D)

120 gm

Answer 2

PE required = mgh = 100 × 10 × 500 = 5 × 10⁵ J

Let W gm of glucose required

\ $\frac{W}{180}$ × 3000 × $\frac{10^{3}}{4}$ = 5 × 10⁵

or $\frac{W}{180}$ ×$\frac{3}{4}$× 10⁶ = 5 × 10⁵

or W = $\frac{2}{3}$× 180 = 120 gm