Question

For the network shown in the figure, the value of the current $i$ is

• A. $\frac{9V}{35}$
• B. $\frac{5V}{18}$
• C. $\frac{5V}{9}$
• D. $\frac{18V}{5}$

Answer 1

Answer: (B)

$\frac{5V}{18}$

Answer 2

The circuit given resembles the balanced Wheatstone Bridge as $\frac{4}{6}=\frac{2}{3}$.
Thus, middle arm containing $4 \Omega$ resistance will be ineffective and no current flows through it. The equivalent circuit is shown as below :