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Question: For the irreversible process, A + B products, the rate is first–order w.r.t. A and second–order w.r....

For the irreversible process, A + B products, the rate is first–order w.r.t. A and second–order w.r.t. B. If 1.0 mol each of A and B introduced into a 1.0 L vessel, and the initial rate was 1.0 × 10–2mol L–1 s–1 , rate when half reactants have been turned into products is :

A

1.25 × 10–3mol L–1 s–1

B

1.0 × 10–2mol L–1 s–1

C

2.50 × 10–3mol L–1 s–1

D

2.0 × 10–2mol L–1 s–1

Answer

1.25 × 10–3mol L–1 s–1

Explanation

Solution

A+BproductA + B\overset{\quad\quad}{\rightarrow}product

r=K[A]1[B]2r = K\lbrack A\rbrack^{1}\lbrack B\rbrack^{2}

r1 = K [1]1 [1]2 = 1 × 10-2 (K = 1 × 10-2)r_{1}\text{ = K }\lbrack 1\rbrack^{1}\text{ }\lbrack 1\rbrack^{2}\text{ } \text{= 1 }\text{×}\text{ 1}\text{0}^{\text{-2}}\ (\text{K = 1 }\text{×}\text{ 1}\text{0}^{\text{-2}})

r1 = K = 1 × 10-2 × = 1.25 × 10-3r_{1}\text{ = K = 1 }\text{×}\text{ 1}\text{0}^{\text{-2}}\text{ }\text{×}\text{ = 1.25 }\text{×}\text{ 1}\text{0}^{\text{-3}}