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Question

Physics Question on Moment Of Inertia

For the given uniform square lamina ABCDABCD, whose centre is OO

A

2IAC=IEF\sqrt{2} I_{A C}=I_{E F}

B

IAD=3IEFI_{A D}=3 I_{E F}

C

IAC=IEFI_{A C}=I_{E F}

D

IAC=2IEFI_{A C}=\sqrt{2} I_{E F}

Answer

IAC=IEFI_{A C}=I_{E F}

Explanation

Solution

Let the each side of square lamina is dd. So, IEF=IGH I_{E F}=I_{G H} (due to symmetry) and IAC=IBD I_{A C}=I_{B D} (due to symmetry) and IAC=IBDI_{A C}=I_{B D} (due to symmetry) Now, according to theorem of perpendicular axis,