Solveeit Logo
Login

Question

Chemistry Question on Equilibrium

For the given reaction, choose the correct expression of KcK_c​ from the following: Fe(aq)3+​+SCN(aq)−​⇌(FeSCN)(aq)2+Fe_{(aq)}^{3+}​+SCN_{(aq)}^{−}​⇌(FeSCN)_{(aq)}^{2+}​

A

Kc=[FeSCN2+][Fe3+][SCN−]K_c = \frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}][\text{SCN}^-]}

B

Kc=[Fe3+][SCN−][FeSCN2+]K_c = \frac{[\text{Fe}^{3+}][\text{SCN}^-]}{[\text{FeSCN}^{2+}]}

C

Kc=[FeSCN2+][Fe3+]2[SCN−]2K_c = \frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}]^2[\text{SCN}^-]^2}

D

Kc=[FeSCN2+]2[Fe3+][SCN−]K_c = \frac{[\text{FeSCN}^{2+}]^2}{[\text{Fe}^{3+}][\text{SCN}^-]}

Answer

Kc=[FeSCN2+][Fe3+][SCN−]K_c = \frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}][\text{SCN}^-]}

Explanation

Solution

The equilibrium constant KcK_c is given by the ratio of the concentration of products to the concentration of reactants.

Kc=[FeSCN2+][Fe3+][SCN−]K_c = \frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}][\text{SCN}^-]}