Question

For the given radioactive decay $^{298}_{94}X → ^{294}_{92}X + ^{4}_{2}ɑ + Q$ - value, binding energy per nucleon of X, Y and ɑ are a, b and c. The Q - value is equal to

• A. 294b + 4c - 298a
• B. 92b + 2c - 94a
• C. 92b + 2c - 94a
• D. 92b + 2c + 94a

Answer 1

Answer: (A)

294b + 4c - 298a

Answer 2

The correct option is (A): 294b + 4c - 298a

Q-value = (B.E)product-(B.E)reaction