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Question: For the given parabola find the coordinates of focus, axis, the equation of the directrix, and the l...

For the given parabola find the coordinates of focus, axis, the equation of the directrix, and the length of the latus rectum.
x2=9y{{x}^{2}}=-9y

Explanation

Solution

Hint: Compare the equation of the parabola x2=9y{{x}^{2}}=-9y with the standard equation of the parabola and get the value of a. The axis of the parabola x2=4ay{{x}^{2}}=-4ay is the y-axis. We know that for the parabola x2=4ay{{x}^{2}}=-4ay , the coordinate of the focus is (0,a)\left( 0,-a \right) , the equation of the directrix is y=ay=a , the length of the latus rectum is 4a. Now, using the value of aa get the coordinates of focus, axis, the equation of the directrix, and the length of the latus rectum.

Complete step-by-step answer:
According to the question, we have a parabola and we have to find the coordinates of focus, axis, the equation of the directrix, and the length of the latus rectum.
The equation of the parabola, x2=9y{{x}^{2}}=-9y ……………………………(1)

The given equation of the parabola is on the form of the standard equation of the parabola x2=4ay{{x}^{2}}=-4ay ………………………(2)
Now, on comparing equation (1) and equation (2), we get

& \Rightarrow -4ay=-9y \\\ & \Rightarrow 4ay=9y \\\ & \Rightarrow 4a=9 \\\ \end{aligned}$$ $$\Rightarrow a=\dfrac{9}{4}$$ ………………………….(3) We know that for the parabola $${{x}^{2}}=-4ay$$ , the coordinate of the focus is $$\left( 0,-a \right)$$ ………………………(4) From equation (3), we have the value of a, $$a=\dfrac{9}{4}$$ . Now, putting the value of $$a$$ in equation (4), we get The coordinate of the focus is $$\left( 0,-\dfrac{9}{4} \right)$$ ………………………………….(5) We also know that for the parabola $${{x}^{2}}=-4ay$$ , the equation of the directrix is $$y=a$$ ………………………..(6) From equation (3), we have the value of a, $$a=\dfrac{9}{4}$$ . Now, putting the value of $$a$$ in equation (6), we get The equation of the directrix is $$y=\dfrac{9}{4}$$ ………………………………………….(7) We know the formula for the length of latus rectum, Latus rectum = $$4a$$ …………………………………..(8) From equation (3), we have the value of a, $$a=\dfrac{9}{4}$$ . Now, putting the value of $$a$$ in equation (8), we get The length of latus rectum, Latus rectum = $$4a=4\times \dfrac{9}{4}=9$$ …………………………………….(10) We know that the axis of the parabola $${{x}^{2}}=-4ay$$ is the y-axis. Since the parabola $${{x}^{2}}=-9y$$ is of the form $${{x}^{2}}=-4ay$$ so, the axis of the parabola $${{x}^{2}}=-9y$$ is also the y-axis and the equation of the y-axis is $$x=0$$ …………………………..(12) Now, from equation (5), equation (7), equation (10), and equation (11), we have The coordinate of the focus is $$\left( 0,-\dfrac{9}{4} \right)$$ . The equation of the directrix is $$y=\dfrac{9}{4}$$ . The length of the latus rectum, Latus rectum = 9. The axis of the parabola is the y-axis i.e, $$x=0$$ . Note: In this question, one might compare the equation of the parabola $${{x}^{2}}=-9y$$ with the standard form that is, $${{y}^{2}}=4ax$$ . This is wrong because the equation of the parabola $${{x}^{2}}=-9y$$ is not in the form of the equation of the parabola, $${{y}^{2}}=4ax$$ . The given equation of the parabola $${{x}^{2}}=-9y$$ is in the form of the standard equation of the parabola $${{x}^{2}}=-4ay$$ . So, we have to compare the equations $${{x}^{2}}=-9y$$ and $${{x}^{2}}=-4ay$$ .