Question

For the given first order reaction A → B, the half-life of the reaction is 0.3010 min. The ratio of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to ______. (Nearest integer)

Answer 1

A→B t $\frac{1}{2}$=0.3010 min $\frac{A_0}{A_t}$ at time 2 min=?
K=$\frac{2.303}{t}$ log $\frac{ A_0}{A_t}$

⇒ $\frac{0.693}{\frac{t1}{2}}$=2.30 $\frac{3}{2}$ log$\frac{ A_0}{A_t}$

Or 2.303×$\frac{0.3010}{0.3010}$=$\frac{2.303}{2}$ log $\frac{ A_0}{A_t}$ log $\frac{ A_0}{A_t}$

=2 ∴$\frac{ A_0}{A_t}$=102=100