Question

For the given equation of charge Q=3t2+6t, where Q is in coulombs and t is time in seconds, the initial value of current is:

• A. 0 A
• B. 2 A
• C. 6 A
• D. 9 A

Answer 1

Answer: (C)

6 A

Answer 2

$\text{ The current is the time derivative of charge:}$
$I = \frac{dQ}{dt} = 6t + 6$
$\text{At } t = 0, \text{ the initial value of current is:}$
$I(0) = 6(0) + 6 = 6 \, \text{A}$
$\text{Thus, the initial current is 6 A.}$