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Physics Question on Electrostatics

For the given diagram, E=ϕxN/C, the net flux through the cube of side x=1 cm, placed at x=1 cm from the origin is:Problem fig

A

2×10−6 Wb2 \times 10^{-6} \, \text{Wb} \\\\

B

1×10−6 Wb1 \times 10^{-6} \, \text{Wb} \\\\

C

3×10−6 Wb3 \times 10^{-6} \, \text{Wb} \\\\

D

4×10−6 Wb4 \times 10^{-6} \, \text{Wb} \\\\

Answer

1×10−6 Wb1 \times 10^{-6} \, \text{Wb} \\\\

Explanation

Solution

Solution: The electric field E=ϕx N/C, where ϕ=1. The flux through the cube is calculated using:\textbf{Solution:} \text{ The electric field } E = \phi x \, \text{N/C}, \text{ where } \phi = 1. \text{ The flux through the cube is calculated using:}
Φ=E×A\Phi = E \times A
Given that the area A is the surface area of the cube and the electric field changes with position, the net flux is computed as:\text{Given that the area } A \text{ is the surface area of the cube and the electric field changes with position, the net flux is computed as:}
Φ=ϕ×1×10−6=1×10−6 Wb\Phi = \phi \times 1 \times 10^{-6} = 1 \times 10^{-6} \, \text{Wb}
Thus, the correct answer is 1×10−6 Wb.\text{Thus, the correct answer is } 1 \times 10^{-6} \, \text{Wb}.