Question

For the given data, the calculation corresponding to all values of pairs (x, y) is following

$\Sigma ( x - \bar { x } ) ^ { 2 } = 36 , \Sigma ( y - \bar { y } ) ^ { 2 } = 25 , \Sigma ( x - \bar { x } ) ( y - \bar { y } ) = 20$

Then the Karl Pearson's correlation coefficient is

$\Sigma ( x - \bar { x } ) ^ { 2 } = 36 , \Sigma ( y - \bar { y } ) ^ { 2 } = 25 , \Sigma ( x - \bar { x } ) ( y - \bar { y } ) = 20$

• A. 0.2
• B. 0.5
• C. 0.66
• D. 0.33

Answer 1

Answer: (C)

0.66

Answer 2

$r _ { x y } = \frac { 20 } { \sqrt { ( 36 ) ( 25 ) } } = \frac { 2 } { 3 } = 0.66$