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Question

Physics Question on Thermodynamics

For the given cyclic process CABCAB as shown for a gas, the work done is :

A

1 J

B

5 J

C

10 J

D

30 J

Answer

10 J

Explanation

Solution

Since P-V indicator diagram is given, so work done by gas is area under the cyclic diagram.
ΔW=\therefore \Delta W = Work done by gas =12×4×5J=\frac{1}{2} \times4 \times5 J
=10J= 10\,J