Question

For the given circuit, in the steady state, $\left| V _{ B ^{-}}- V _{ D }\right|=$___$V$

Answer 1

In steady state, capacitor behaves as an open circuit. Circuit is:

$⇒ i_{AB}=\frac{6}{3}=2A\ \&\ i_{AD}=\frac{6}{12}=0.5A$
$⇒$ VB + 2 × 2 - 10 × 0.5 = VD
$⇒$ VB + VD = 1 volt
So, the correct answer is 1.