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Question: For the following chemical reaction:\( 2HBr(aq) + Ba{(OH)_2} \to 2{H_2}O(l) + BaB{r_2}(aq)\), how do...

For the following chemical reaction:2HBr(aq)+Ba(OH)2→2H2O(l)+BaBr2(aq) 2HBr(aq) + Ba{(OH)_2} \to 2{H_2}O(l) + BaB{r_2}(aq), how do you write the net ionic equation, including the phases?

Explanation

Solution

The net ionic equation is defined as the equation where the ions which undergo changes during the reaction is only represented which means the compound which is soluble on water and dissociates to give its ion.

Complete step by step answer: The net ionic equation is a chemical equation which represents the chemical species or ions taking part in the chemical reaction. The net ionic equation is written with the help of the balanced chemical equation.
The balanced chemical equation is defined as the equation where the number of moles of elements present in the left side of the reaction is the same as the number of elements present in the right side of the reaction.
As we know that the strong electrolyte is highly soluble in water and dissolves to give its constituent ions.
The given balanced chemical reaction is shown below.
2HBr(aq)+Ba(OH)2→2H2O(l)+BaBr2(aq)2HBr(aq) + Ba{(OH)_2} \to 2{H_2}O(l) + BaB{r_2}(aq)
In this reaction two mole of hydrogen bromide reacts with one mole of barium hydroxide to form two mole of water and one mole of barium bromide.
The ionic equation of the given reaction is shown below.
2H+(aq)+2Br−(aq)+Ba2+(aq)+2OH−(aq)→2H2O(l)+Ba2+(aq)+2Br−(aq)2{H^ + }(aq) + 2B{r^ - }(aq) + B{a^{2 + }}(aq) + 2O{H^ - }(aq) \to 2{H_2}O(l) + B{a^{2 + }}(aq) + 2B{r^ - }(aq)
Remove the spectator ions from both sides of the equation, to obtain the net ionic equation of the balanced chemical equation.
The spectator ions are defined as those ions which are common in both sides of the reaction.
The net ionic equation obtained from the ionic equation is shown below.
2H+(aq)+2OH−(aq)→2H2O(l)2{H^ + }(aq) + 2O{H^ - }(aq) \to 2{H_2}O(l)

Note:
The weak electrolytes do not give the net ionic equation as they partially dissociate to give their respective ions in the solution. Make sure to cancel out the spectator ions as it is the only step which helps to differentiate between ionic equation and net ionic equation.