For the equilibrium,({ MgCO\_3(s) <=>\[\triangle] MgO(s)+CO\... | Chemistry | SolveeIt

Question

For the equilibrium, ${ MgCO_3(s) <=>[\triangle] MgO(s)+CO_2 (g)}$ which of the following expressions is correct ?

$K_P=P_{CO_2}$

$K_P=\frac {[MgO][CO_2]}{[MgCO_3]}$

$K_P=\frac {P_{mgO}.P_{CO_2}}{P_{MgCO_3}}$

$K_P=\frac {P_{mgO}+P_{CO_2}}{P_{MgCO_3}}$

Answer

$K_P=P_{CO_2}$

Explanation

Solution

In heterogeneous system, $K_C$ and $K_P$ are not depend upon the concentration or pressure of solid substance. Hence, at equilibrium their concentration or pressure are assumed as one.
${ MgCO_3(s) <=> MgO(s)+CO_2(g)}$
$\therefore$ $K_P=P_{CO_2}$

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