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Question: For the equilibrium CH3 – CH2 – CH2 – CH3(g) <img src="https://cdn.pureessence.tech/canvas_184.png?t...

For the equilibrium CH3 – CH2 – CH2 – CH3(g) equilibrium constant is found to be 1.732 at 298 K. Now if in a vessel at 298 K, a mixture of these two gases be taken as represented by the point P in the figure, predict what will happen

A

Immediately, above equilibrium will be setup

B

Above reaction will go in the forward direction till it attains equilibrium

C

Above reaction will go in the backward direction till it attains equilibrium

D

Nothing can be said

Answer

Above reaction will go in the backward direction till it attains equilibrium

Explanation

Solution

From given information,

Q=tan750=conc.ofisobutaneconc,ofnbutane>KC=3Q = \tan{}75^{0} = \frac{conc.ofisobu\tan e}{conc,ofn - bu\tan e} > K_{C} = \sqrt{3}

so backward reaction