Question

For the equation 3x² + Px + 3 = 0, P > 0 if one root of the

equation is square of the other then P equals

• A. 1/3
• B. 1
• C. 3
• D. 2/3

Answer 1

Answer: (C)

3

Answer 2

3x² + px + 3 = 0

Let the roots be a, b so let a² = b

Now a + a² = –$\frac{p}{3}$

a. a² = $\frac{3}{3}$= 1

We know w + w² = –1, w³ = 1

on comparing

p = 3