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Question

Question: For the data | | | | | | | |-----|-----|-----|-----|-----|-----| | x : | 4 ...

For the data

x :47834
y :58635

the Karl Pearson coefficient is

A

6394×66\frac{63}{\sqrt{94 \times 66}}

B

63

C

6394\frac{63}{\sqrt{94}}

D

6366\frac{63}{\sqrt{66}}

Answer

6394×66\frac{63}{\sqrt{94 \times 66}}

Explanation

Solution

Construct the following table taking A=5A = 5 and B=5B = 5.

xiyi

ui=

$0.8 = \sqrt{0.2 \times b_{yx}} \Rightarrow b_{yx} = \frac{0.64}{0.2} = 3.2$ – 5

vi=

yi – 5

ui2vi2uivi

4

7

8

3

4

5

8

6

3

5

– 1

2

3

– 2

– 1

0

3

1

– 2

0

1

4

9

4

1

0

9

1

4

0

0

6

3

4

0

Total12191413

r(X,Y)=131×25191251445r ( X , Y ) = \frac { 13 - \frac { 1 \times 2 } { 5 } } { \sqrt { 19 - \frac { 1 ^ { 2 } } { 5 } } \sqrt { 14 - \frac { 4 } { 5 } } } xˉ=n1xˉ1+n2xˉ2n1+n2\bar{x} = \frac{n_{1}{\bar{x}}_{1} + n_{2}{\bar{x}}_{2}}{n_{1} + n_{2}}