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Chemistry Question on Colloids

For the coagulation of positively charged hydrated ferric-oxide sol, the flocculating power of the ions is in the order :

A

PO43−>SO42−>Cl−>[Fe(CN)6]4−PO_4^{3-}\gt SO_4^{2-}\gt Cl^{-}\gt[Fe(CN)_6]^{4-}

B

Cl−>SO42−>PO43−>[Fe(CN)6]4−Cl^{-}\gt SO_4^{2-}\gt PO_4^{3-}\gt[Fe(CN)_6]^{4-}

C

SO42−=Cl−=PO43−=[Fe(CN)6]4−SO_4^{2-}= Cl^{-}= PO_4^{3-}=[Fe(CN)_6]^{4-}

D

[Fe(CN)6]4−>PO43−>SO42−>Cl−[Fe(CN)_6]^{4-}\gt PO_4^{3-}\gt SO_4^{2-}\gt Cl^{-}

Answer

[Fe(CN)6]4−>PO43−>SO42−>Cl−[Fe(CN)_6]^{4-}\gt PO_4^{3-}\gt SO_4^{2-}\gt Cl^{-}

Explanation

Solution

The correct answer is Option (D) : [Fe(CN)6]4−>PO43−>SO42−>Cl−[Fe(CN)_6]^{4-}\gt PO_4^{3-}\gt SO_4^{2-}\gt Cl^{-}