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Question

Physics Question on Semiconductor electronics: materials, devices and simple circuits

For the circuit shown below, the current through the Zener diode is :

A

5mA5\, mA

B

Zero

C

14mA14\, mA

D

9mA9 \,mA

Answer

9mA9 \,mA

Explanation

Solution

Assuming zener diode doesnot undergo breakdown, current in circuit = 12015000=8mA\frac{120}{15000} = 8mA
\therefore Voltage drop across diode = 80V>50V80 V > 50 V.
The diode undergo breakdown.
Current is R1=705000=14mAR_1 = \frac{70}{5000} = 14 \,mA
Current is R2=5010000=5mAR_2 = \frac{50}{10000} = 5 \,mA
\therefore Current through diode = 9mA9\,mA