Solveeit Logo

Question

Question: For the circle x2 + y2 – 2x – 6y + 1 = 0 the chord of minimum length and passing through (1, 2) is o...

For the circle x2 + y2 – 2x – 6y + 1 = 0 the chord of minimum length and passing through (1, 2) is of length-

A

22\sqrt{2}

B

42\sqrt{2}

C

62\sqrt{2}

D

82\sqrt{2}

Answer

42\sqrt{2}

Explanation

Solution

Length of the chord = 2r2p2\sqrt{r^{2} - p^{2}} = l

lminimum = pmaximum