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Question: For the chemical equilibrium, \(\mathrm { CaCO } _ { 3 } ( s )\) ⇌ <img src="https://cdn.pureesse...

For the chemical equilibrium, CaCO3(s)\mathrm { CaCO } _ { 3 } ( s ) ⇌

can be determined from which one of the following plots.

A
B
C
D
Answer
Explanation

Solution

For the reaction,

CaCO3(g) ⇌ CaO(s) + CO2(g)

Kp = and KC = [CO2]

( [CaCO3] = 1 and [CaO] = 1 for solids]

According to Arrhenius equation we have

Taking logarithm, we have

log⁡Kp=log⁡A−ΔHroRT(2.303)\log K _ { p } = \log A - \frac { \Delta H _ { r } ^ { o } } { R T ( 2.303 ) }

This is an equation of straight line. When log Kp is plotted against 1 / T. we get a straight line.

log⁡pCO2\log p _ { \mathrm { CO } _ { 2 } }

The intercept of this line = log A, slope = –∆H°r / 2.303 R

Knowing the value of slope from the plot and universal gas constant R, ∆Hr° can be calculated.

(Equation of straight line : Y = mx + C. Here,

log⁡Kp=−ΔHro2.303R(1T)+log⁡A\log K _ { p } = - \frac { \Delta H _ { r } ^ { o } } { 2.303 R } \left( \frac { 1 } { T } \right) + \log A

Y m x C